CBSE Solutions for Class 11 Maths

Select CBSE Solutions for class 10 Subject & Chapters Wise :

Find 11th term of the A.P. 1, 4, 7, 10, ....

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Answer :

31

Find 12th term of the A.P. 1, 4, 7, 10, ...

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Answer :

34

Find 13th term of the A.P. 1, 4, 7, 10,...

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Answer :

37

Find 14th term of the A.P. 1, 4, 7, 10,...

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Answer :

40

Find 15th term of the A.P. 1, 4, 7, 10,...

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Answer :

43

Find 16th term of the A.P. 1, 4, 7, 10,...

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Answer :

46

Find 17th term of the A.P. 1, 4, 7, 10,...

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Answer :

49

Find 18th term of the A.P. 1, 4, 7, 10,...

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Answer :

52

Find 19th term of the A.P. 1, 4, 7, 10,...

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Answer :

55

Find 20th term of the A.P. 1, 4, 7, 10,...

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Answer :

58

Find 17th term of the A.P. √2, 3√2, 5√2,...

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Answer :

33√2

Find 16th term of the A.P. √2, 3√2, 5√2,...

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Answer :

31√2

Find 15th term of the A.P. √2, 3√2, 5√2,...

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Answer :

29√2

Find 14th term of the A.P. √2, 3√2, 5√2,...

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Answer :

27√2

Find 13th term of the A.P. √2, 3√2, 5√2,...

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Answer :

25√2

Find 19th term of the A.P. √2, 3√2, 5√2,...

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Answer :

37√2

Find 20th term of the A.P. √2, 3√2, 5√2,...

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Answer :

39√2

Find 21th term of the A.P. √2, 3√2, 5√2,...

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Answer :

41√2

Find 22th term of the A.P. √2, 3√2, 5√2,...

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Answer :

43√2

Find 23th term of the A.P. √2, 3√2, 5√2,...

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Answer :

45√2

Which term of the A.P. 3, 8, 13, ... is 243?

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Answer :

3, 8, 13...
Here, we have:
a = 3
d = (8-3)  =5
Let an = 243

⇒ a+(n-1)d = 243

⇒3+(n-1)5 = 243

⇒(n-1)5 =240

n-1 = 48

⇒ n= 49

Hence, 243 is the 49th term of the given A.P.

Which term of the A.P. 80, 76, ... is 0?

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Answer :

84, 80, 76...
Here, we have:
a = 80
d = (76-80) = -4
Let an =0

a+(n-1)d = 0

⇒80 + (n-1)(-4) = 0

⇒ (n-1)(-4) = -80

⇒(n-1) = 20⇒ n = 21

Hence, 0 is the 21nd term of the given A.P.

Which term of the A.P. 4, 9, 14, ... is 249?

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Answer :

4, 9, 14...
Here, we have:
a = 4
d = (9-4) = 5
Let an = 249

a+(n-1) d = 249

⇒4+(n-1) 5 = 249

⇒(n-1) 5 =245

⇒(n-1) = 49⇒ n= 50

Hence, 249 is the 50th term of the given A.P.

Which term of the A.P. 3, 8, 13, ... is 253?

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Answer :

3, 8, 13...
Here, we have:
a = 3
d = (8-3)  =5
Let an = 253

⇒ a+(n-1)d = 253

⇒3+(n-1)5 = 253

⇒(n-1)5 =250

n-1 = 40

⇒ n= 51

Hence, 253 is the 51th term of the given A.P.

Which term of the A.P. 80, 76, ... is 4?

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Answer :

84, 80, 76...
Here, we have:
a = 80
d = (76-80) = -4
Let an =4

a+(n-1)d = 4

⇒80 + (n-1)(-4) = 4

⇒ (n-1)(-4) = -76

⇒(n-1) = 19

⇒ n = 20

Hence, 4 is the 20th term of the given A.P.

 Which term of the A.P. 4, 9, 14, ... is 259?

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Answer :

4, 9, 14...
Here, we have:
a = 4
d = (9-4) = 5
Let an = 259

a+(n-1) d = 259

⇒4+(n-1) 5 = 259

⇒(n-1) 5 =255

⇒(n-1) = 51⇒ n= 52

Hence, 255 is the 52th term of the given A.P.

Is 67 a term of the A.P. 7, 10, 13, ...?

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Answer :

7, 10, 13...
Here, we have:
a = 7
d = (10-7) = 3

Let an = 67

⇒ a+(n-1) d = 67

⇒7+(n-1)(3) = 67

⇒(n-1)(3) = 60

⇒(n-1) = 60/3

n =  20 +1 = 21

Since n is a natural number. So, 67 is a term of the given A.P.

Is 301 a term of the A.P. 3, 8, 13, ...?

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Answer :

3, 8, 13...
Here, we have:
a  = 3
d = (8-3)=5

Let an = 301

⇒ a+(n-1)d = 301

⇒3+(n-1)5 = 301

⇒(n-1)5 =298

⇒(n-1) = 298/5

n = 298/5 + 1 = 303/5
Since n is not a natural number.So, 301 is not a term of the given A.P.

Is 69 a term of the A.P. 7, 10, 13, ...?

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Answer :

7, 10, 13...
Here, we have:
a = 7
d = (10-7) = 3

Let an = 69

⇒ a+(n-1) d = 69

⇒7+(n-1)(3) = 69

⇒(n-1)(3) = 62

⇒(n-1) = 62/3

n =  62/3 +1 = 65/3

Since n is not a natural number. So, 69 is not a term of the given A.P.

Is 303 a term of the A.P. 3, 8, 13, ...?

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Answer :

3, 8, 13...
Here, we have:
a  = 3
d = (8-3)=5

Let an = 303

 a+(n-1)d = 303

3+(n-1)5 = 303

(n-1)5 =300

(n-1) = 300/5

n = 60 + 1 = 61
Since n is a natural number. So, 303 is a term of the given A.P.

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