# CBSE Solutions for Class 11 Maths

#### Select CBSE Solutions for class 10 Subject & Chapters Wise :

Find 11th term of the A.P. 1, 4, 7, 10, ....

31

Find 12th term of the A.P. 1, 4, 7, 10, ...

34

Find 13th term of the A.P. 1, 4, 7, 10,...

37

Find 14th term of the A.P. 1, 4, 7, 10,...

40

Find 15th term of the A.P. 1, 4, 7, 10,...

43

Find 16th term of the A.P. 1, 4, 7, 10,...

46

Find 17th term of the A.P. 1, 4, 7, 10,...

49

Find 18th term of the A.P. 1, 4, 7, 10,...

52

Find 19th term of the A.P. 1, 4, 7, 10,...

55

Find 20th term of the A.P. 1, 4, 7, 10,...

58

Find 17th term of the A.P. √2, 3√2, 5√2,...

33√2

Find 16th term of the A.P. √2, 3√2, 5√2,...

31√2

Find 15th term of the A.P. √2, 3√2, 5√2,...

29√2

Find 14th term of the A.P. √2, 3√2, 5√2,...

27√2

Find 13th term of the A.P. √2, 3√2, 5√2,...

25√2

Find 19th term of the A.P. √2, 3√2, 5√2,...

37√2

Find 20th term of the A.P. √2, 3√2, 5√2,...

39√2

Find 21th term of the A.P. √2, 3√2, 5√2,...

41√2

Find 22th term of the A.P. √2, 3√2, 5√2,...

43√2

Find 23th term of the A.P. √2, 3√2, 5√2,...

45√2

Which term of the A.P. 3, 8, 13, ... is 243?

3, 8, 13...
Here, we have:
a = 3
d = (8-3)  =5
Let an = 243

⇒ a+(n-1)d = 243

⇒3+(n-1)5 = 243

⇒(n-1)5 =240

n-1 = 48

⇒ n= 49

Hence, 243 is the 49th term of the given A.P.

Which term of the A.P. 80, 76, ... is 0?

84, 80, 76...
Here, we have:
a = 80
d = (76-80) = -4
Let an =0

a+(n-1)d = 0

⇒80 + (n-1)(-4) = 0

⇒ (n-1)(-4) = -80

⇒(n-1) = 20⇒ n = 21

Hence, 0 is the 21nd term of the given A.P.

Which term of the A.P. 4, 9, 14, ... is 249?

4, 9, 14...
Here, we have:
a = 4
d = (9-4) = 5
Let an = 249

a+(n-1) d = 249

⇒4+(n-1) 5 = 249

⇒(n-1) 5 =245

⇒(n-1) = 49⇒ n= 50

Hence, 249 is the 50th term of the given A.P.

Which term of the A.P. 3, 8, 13, ... is 253?

3, 8, 13...
Here, we have:
a = 3
d = (8-3)  =5
Let an = 253

⇒ a+(n-1)d = 253

⇒3+(n-1)5 = 253

⇒(n-1)5 =250

n-1 = 40

⇒ n= 51

Hence, 253 is the 51th term of the given A.P.

Which term of the A.P. 80, 76, ... is 4?

84, 80, 76...
Here, we have:
a = 80
d = (76-80) = -4
Let an =4

a+(n-1)d = 4

⇒80 + (n-1)(-4) = 4

⇒ (n-1)(-4) = -76

⇒(n-1) = 19

⇒ n = 20

Hence, 4 is the 20th term of the given A.P.

Which term of the A.P. 4, 9, 14, ... is 259?

4, 9, 14...
Here, we have:
a = 4
d = (9-4) = 5
Let an = 259

a+(n-1) d = 259

⇒4+(n-1) 5 = 259

⇒(n-1) 5 =255

⇒(n-1) = 51⇒ n= 52

Hence, 255 is the 52th term of the given A.P.

Is 67 a term of the A.P. 7, 10, 13, ...?

7, 10, 13...
Here, we have:
a = 7
d = (10-7) = 3

Let an = 67

⇒ a+(n-1) d = 67

⇒7+(n-1)(3) = 67

⇒(n-1)(3) = 60

⇒(n-1) = 60/3

n =  20 +1 = 21

Since n is a natural number. So, 67 is a term of the given A.P.

Is 301 a term of the A.P. 3, 8, 13, ...?

3, 8, 13...
Here, we have:
a  = 3
d = (8-3)=5

Let an = 301

⇒ a+(n-1)d = 301

⇒3+(n-1)5 = 301

⇒(n-1)5 =298

⇒(n-1) = 298/5

n = 298/5 + 1 = 303/5
Since n is not a natural number.So, 301 is not a term of the given A.P.

Is 69 a term of the A.P. 7, 10, 13, ...?

7, 10, 13...
Here, we have:
a = 7
d = (10-7) = 3

Let an = 69

⇒ a+(n-1) d = 69

⇒7+(n-1)(3) = 69

⇒(n-1)(3) = 62

⇒(n-1) = 62/3

n =  62/3 +1 = 65/3

Since n is not a natural number. So, 69 is not a term of the given A.P.

Is 303 a term of the A.P. 3, 8, 13, ...?

3, 8, 13...
Here, we have:
a  = 3
d = (8-3)=5

Let an = 303

a+(n-1)d = 303

3+(n-1)5 = 303

(n-1)5 =300

(n-1) = 300/5

n = 60 + 1 = 61
Since n is a natural number. So, 303 is a term of the given A.P.