જવાબ : **Given Ap is 213, 205, 197, ... , 37.**
**Here, first term, a=213; common difference, d=205-213=-8, **
**n ^{th} term,**

જવાબ : **Given that 2K+1, 3K+3 ad 5K+1 are in A.P.**
**so, (3K+3) - (2k+1) = (5K-1) - (3k+3)**
**=> K+2 = 2K-4**
**=> 2K-K = 2 + 4 => K=6**

જવાબ : **Given that K+9, 2K-1 ad 2K+7 are in A.P.**
**so, (2K-1) - (k+9) = (2K+7) - (2k-1)**
**=> K-10 = 8**
** => K=18**

જવાબ : Reversing the given A.P., we get
185,181,174,...,9,5
Now, first term(a) =185
Common difference, (d) =181 -185 = -4
We know that nth term of an A.P. is given by a+(n-1)d
Ninth term a_{9} = a+(9-1)d
=185+8x(-4) = 185-32= 153

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જવાબ : Given that,

11જવાબ : Given that,

3જવાબ : Given,

જવાબ : Given two APs as; 63, 65, 67,… and 3, 10, 17,….

Taking first AP, 63, 65, 67, … First term, a = 63 Common difference, d = aજવાબ : The first multiple of 4 that is greater than 10 is 12.

Next multiple will be 16. Therefore, the series formed as; 12, 16, 20, 24, … All these are divisible by 4 and thus, all these are terms of an A.P. with first term as 12 and common difference as 4. When we divide 250 by 4, the remainder will be 2. Therefore, 250 − 2 = 248 is divisible by 4. The series is as follows, now; 12, 16, 20, 24, …, 248 Let 248 be theજવાબ : First three-digit number that is divisible by 7 are;

First number = 105 Second number = 105+7 = 112 Third number = 112+7 =119 Therefore, 105, 112, 119, … All are three digit numbers are divisible by 7 and thus, all these are terms of an A.P. having first term as 105 and common difference as 7. As we know, the largest possible three-digit number is 999. When we divide 999 by 7, the remainder will be 5. Therefore, 999-5 = 994 is the maximum possible three-digit number that is divisible by 7. Now the series is as follows. 105, 112, 119, …, 994 Let 994 be the nth term of this A.P. first term, a = 105 common difference, d = 7 aજવાબ : Let, the first term of two APs be *a*_{1} and *a*_{2} respectively

જવાબ : Given A.P. is 3, 15, 27, 39,

જવાબ : We know that, for an A.P series;

જવાબ : Given that,

જવાબ : Given A.P. is3, 8, 13, …, 253

Common difference, d= 5. Therefore, we can write the given AP in reverse order as; 253, 248, 243, …, 13, 8, 5 Now for the new AP, first term, a = 253 and common difference, d = 248 − 253 = −5 n = 20 Therefore, using nth term formula, we get,જવાબ : We know that, the nth term of the AP is;

જવાબ : It can be seen from the given question, that the incomes of Subba Rao increases every year by Rs.200 and hence, forms an AP.

Therefore, after 1995, the salaries of each year are; 5000, 5200, 5400, … Here, first term,જવાબ : Given that, Ramkali saved Rs.5 in first week and then started saving each week by Rs.1.75.

Hence, First term, a = 5 and common difference, d = 1.75 Also given,જવાબ :

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gseb maths textbook std 10

- Math Book for GSEB ધોરણ ૧૦
- Chemistry Book for GSEB ધોરણ ૧૦
- Biology Book for GSEB ધોરણ ૧૦
- Physics Book for GSEB ધોરણ ૧૦
- History Book for GSEB ધોરણ ૧૦
- Geography Book for GSEB ધોરણ ૧૦
- Economics Book for GSEB ધોરણ ૧૦
- Political Science Book for GSEB ધોરણ ૧૦

The GSEB Books for class 10 are designed as per the syllabus followed Gujarat Secondary and Higher Secondary Education Board provides key detailed, and a through solutions to all the questions relating to the GSEB textbooks.

The purpose is to provide help to the students with their homework, preparing for the examinations and personal learning. These books are very helpful for the preparation of examination.

For more details about the GSEB books for Class 10, you can access the PDF which is as in the above given links for the same.