LOADING . . .
જવાબ : Positive, Negative
જવાબ : Voltmeter
જવાબ : Electric Current
જવાબ : Low
જવાબ : Electric power
જવાબ : Nitrogen
જવાબ : ampere
જવાબ : Ohm’s, current, temperature
જવાબ : length, area of crosssection, material
જવાબ : ohmmeter (Ω m)
જવાબ : doubled
જવાબ : Electric potential at a point in an electric field is defined as the work done in moving a unit positive charge from infinity to that point in the electric field.
જવાબ : V = W/q.
જવાબ : volt.
જવાબ : Electric potential is said to be 1 volt if 1 Joule of work is done in moving 1 coulomb charge from infinity to a point in the electric field.
જવાબ : Electric potential is a scalar physical quantity.
જવાબ : Work done per unit charge in moving a unit positive charge from one point to another point in an electric field is called potential difference between two points.
જવાબ : Voltmeter.
જવાબ :
જવાબ : Potential difference across the ends of the conductor.
જવાબ : Electric current is defined as the amount of electric charge flowing through any crosssection of a conductor per unit time.
જવાબ :
જવાબ : I = ne/t.
જવાબ : ampere (A)
જવાબ : Electric current through a conductor is said to be 1 ampere if 1 coulomb electric charge flows through a crosssection of a conductor in 1 second.
જવાબ : The direction of electric current in a wire is just opposite to the direction of flow of electrons in the wire.
જવાબ : Ammeter.
જવાબ : Ammeter is connected in series in an electric circuit.
જવાબ : Voltmeter is connected in parallel across a conductor or resistor in the electric circuit.
જવાબ : Ohm’s law states that the electric current flowing through a conductor is directly proportional to the potential difference across the ends of the conductor, provided the temperature and . Other physical conditions of the conductor remain the same.
જવાબ : The potential difference (V) is directly proportional to the current (I).
જવાબ :
જવાબ : V ∝ I or V = IR or I = V/R .
જવાબ : It is the property of a conductor to oppose the flow of electric charge through it.
Resistance of a conductor, R = V/I , where V is the potential difference across the conductor and I is the current flowing through the conductor.
જવાબ : ohm (Ω).
જવાબ : The resistance of a conductor is said to be 1Ω if a potential difference of IV across the ends of the conductor makes a current of 1A to flow through it.
જવાબ : A straight line passing through the origin and has constant slope.
જવાબ : y = R. Therefore, physical quantity is resistance of a conductor.
જવાબ : Therefore, slope of VI graph represents reciprocal of the resistance of a conductor resistance of a conductor.
જવાબ : Resistance of a conductor increases with the increase in temperature.
જવાબ : Slope of IV graph = resistance of metallic conductor.
Since, slope of IV graph at temperature T_{2} is greater than the slope of IV graph at temperature T_{1}, therefore, resistance at T_{2} is greater than resistance at T_{1} . Since, resistance of a metallic conductor increases with increase in temperature, therefore, T_{2} > T_{1}.
જવાબ : Resistance of a wire is inversely proportional to its crosssectional area. More is crosssectional area of a conductor, less is the resistance of the conductor.
જવાબ : where R is the resistance, A is the area of crosssection and l is the length of the substance.
જવાબ : Electrical resistivity of a material is defined as the resistance of an object (made of the material) of unit length and unit area of crosssection.
જવાબ : ohmmetre (Ωm).
જવાબ : New resistivity will also be ‘ρ’ because resistivity of a wire does not depend on its length.
જવાબ : Resistivity of metal < resistivity of alloy < resistivity of insulator.
જવાબ : R_{eff} = R_{1} + R_{2} + R_{3} + … upto n = nR
જવાબ :
જવાબ :
જવાબ : Electric current is defined as the amount of charge flowing through a crosssection of a conductor in unit time.
SI unit of electric current is ampere (A).જવાબ :
Ammeter

Voltmeter

1. Ammeter measures electric current in the circuit.
2. Ammeter is connected in series in an electric circuit.

1. Voltmeter measures the potential difference between two points on a conductor.
2. Voltmeter is connected in parallel across the ends of a conductor or resistor.

જવાબ : electric circuit:
An electric circuit is a closed conducting path containing a source of electric energy (i.e., a cell or a battery) and a device or element or load (say, an electric bulb) utilizing the electric energy.
The direction of electric current is opposite to the direction of the flow of electrons in the conductor.
Open electric circuit : An electric circuit through which no electric current flows is known as open electric circuit.
The electric circuit showed in figure 10 (A) will be open circuit if the plug of the key is taken out or if the connecting wire breaks from any point.
જવાબ : (i) It represents a closed plug key. It is used to make the closed electric circuit.
(ii) It represents a variable resistance. It is used to increase or decrease the electric current in the circuit.
(iii) It represents a voltmeter. It is used to measure the potential difference across a resistor in the circuit.
(iv) It represents a galvanometer. It is used to detect the presence of small current in the circuit.
(v) It represents wire crossing (not connected with each other). The wires are used to connect various components in the circuit.
જવાબ :
The current will be high if resistance is low. p and l for both wires A and B are same but area of crosssection (A) of wire A is more than the wire B. Therefore, resistance of wire A is less than the resistance of the wire B. Hence, ammeter A connected in series with the wire A will indicate higher reading for current.જવાબ : The current in the circuit is high if the resistance of the circuit is low. Since wire A is longer than B, so the resistance of wire B is less than the resistance of wire A. Hence, current flowing through wire B is greater than the current flowing through wire A. Therefore, ammeter A_{2} will indicate higher reading of current.
જવાબ : Resistance of a conductor = slope of IV graph. It means, resistance is high if slope of IV graph for it is steeper. Since R_{1} > R_{2}, therefore, slope of IV graph for R_{1} must be steeper than the slope of IV graph for R_{2} Thus, diagram I represents the situation correctly.
જવાબ : The given circuit is incorrect because in a circuit, ammeter is always connected in series and voltmeter is connected parallel to the resistor R_{1}. The correct circuit is shown in figure.
જવાબ :
જવાબ :
Salient features of series combination :જવાબ : It should be made of nichrome wire because
જવાબ : Heat produced in a heater, when connected to main supply,
When identical heaters (i.e. having same resistance) are connected in parallel, their net resistance decreases as compared to when connected in series. Therefore, heaters connected in parallel would heat the water faster as the heat produced in parallel combination is more than the heat produced in series combination, on electric energy and electric power.જવાબ : Electric power is defined as the amount of electric work or electric energy per unit time.
If W be the amount of electric energy consumed in a circuit in t seconds, then the electric power is given by
જવાબ : For Ohm’s law: Ohm’s law states that the electric current flowing through a conductor is directly proportional to the potential difference across the ends of the conductor, provided the temperature and . other physical conditions of the conductor remain the same.
For experimental verification: Verify Ohm’s law
Apparatus: A conductor of resistance R, an ammeter, a voltmeter, a battery, a variable resistance (or rheostat used to change the current in the circuit), connecting wires, a key and sand paper.
Procedure:
જવાબ :
જવાબ :
જવાબ :
જવાબ :
Charge = q = ne
જવાબ : Mathematically, resistivity of the conducting material is given by
p = R x A/J
If l = 1 m, A = 1 m^{2}, then p = R
Hence, the resistivity of the material is defined as the resistance offered by a metallic wire having a unit length and a unit area of crosssection. Since unit length and unit area of crosssection forms a cube, the specific resistance or resistivity can also be defined as the resistance offered by a cube of a material of side 1 m when current flows perpendicularly through the opposite faces. In SI system, its units are
જવાબ : (a) Difference between electric energy and electric power:
i.e. less the power of electrical device, higher is its electrical resistance.જવાબ : Ohm’s law : When the physical conditions such as temperature etc. remain same, the current flowing through the conductor is directly proportional to the potential difference applied across the ends of the conductor, i.e.,
Necessary condition for validity of Ohm’s law is that physical condition such asજવાબ : Greater than slope of VI graph, greater will be the resistance of given metallic wire. In the given graph, wire A has greater slope then B. Hence, wire A has greater resistance.
For the wires of same length and same thickness, resistance depends on the nature of material of the wire, i.e.
જવાબ :
Aim: Same current flows through every part of the above circuit.જવાબ :
So, for different materials having same resistance per unit length, greater resistivity material wire has more crosssectional area.જવાબ : (a) Electric power: It is the rate of doing work by an energy source or the rate at which the electrical energy is dissipated or consumed per unit time in the electric circuit is called electric power.
(b) It means, the maximum current will flow through it is only 2 A. Fuse wire will melt if the current exceeds 2 A value through it.જવાબ : Power of the bulb,
જવાબ : The resistivity of nichrome is more than that of copper so its resistance is also high. Therefore, large amount of heat is produced in the nichrome wire for the same current as compared to that of copper wire. Accordingly, more change in temperature is observed in the nichrome wire. This is explained by Joule’s law of heating.
Joule’s law of heating: It states that the amount of heat produced in a conductor is
જવાબ :
Current drawn by bulb at 192 V isજવાબ : (i) Bulbs in parallel provide more illumination. This is because
(a) each bulb gets same voltage and is equal to the applied voltage.
(b) each bulb draws required current from the mains. Hence, they work properly.
(ii)When one bulb in each circuit gets fused,
In series: Rest of the bulbs will not glow. This is because in series arrangement, there is only a single path for the flow of current.
In parallel: Rest of the bulbs will continue to glow as in parallel connection,
(a) individual branch in the circuit completes its own circuit, or
(b) different paths are available for the flow of current.
(iii) Circuit diagram
જવાબ : (a) Electric line wires offer extremely low resistance to the flow of current, so
they do not glow because negligible heat is produced in it.
The filament of bulb glows because it becomes red hot due to large amount of
heat produced, as it offers high resistance to the flow of current through it.
(b) The filament of bulb when it glows at 2700°C does not get burnt because the tungsten metal of filament has
(i) a very high melting point (of 3380°C) and
(ii) a high resistivity.
જવાબ : (a)(i) Ammeter reading in the second case is half of the ammeter reading
in first case. This is because
=> i.e. when length is doubled, the resistance is doubled, this means the current is halved.
(ii) On doubling the area of crosssection without changing the length of the conductor, twice of the previous reading is observed in the ammeter. This is because
So, when A is double, resistance becomes half, current will be doubled. (b) “Potential difference between points A and B in an electric field is 1 V”. It means 1 J work is done in moving 1 C of charge from point B to point A in an electric field.
Column I

Column II

(a) Resistance

(i) Infinite

(b) The rate of flow of charge

(ii) Potential difference

(c) The work done to move a unit charge

(iii) Obstruction to the flow of current
from one point to another 
(d) Resistance of ideal ammeter

(iv) Watt

(e) Resistance of ideal voltmeter

(v) Electric current

(f) SI unit of electric power

(vi) Zero

જવાબ :
Column I

Column II

(a) Resistance

(iii) Obstruction to the flow of current
from one point to another 
(b) The rate of flow of charge

(v) Electric current

(c) The work done to move a unit charge

(ii) Potential difference

(d) Resistance of ideal ammeter

(vi) Zero

(e) Resistance of ideal voltmeter

(i) Infinite

(f) SI unit of electric power

(iv) Watt

a. The device which measures current 
fuse 
b. The device which measures potential difference 
parallel 
c. The device which protect electric appliances from high current 
ammeter 
d. SI unit of voltage 
volt 
e. Combination used for household use 
kilowatt hour 
f . Commercial unit of energy

voltmeter 
જવાબ :
a. The device which measures current (ammeter)
b. The device which measures potential difference (voltmeter)
c. The device which protect electric appliances from high current (fuse)
d. SI unit of voltage (volt)
e. Combination used for household use (parallel)
f. Commercial unit of energy (kilowatt hour)
a. Bulb is usually filled with 
ampere 
b. SI unit of current 
potential difference 
c. Flow of current in a wire is due to 
nitrogen 
જવાબ :
a. Bulb is usually filled with (nitrogen)
b. SI unit of current (ampere)
c. Flow of current in a wire is due to (potential difference)
.
આ પ્રકરણને લગતા વિવિધ એનિમેશન વિડીયો, હેતુલક્ષી પ્રશ્નો, ટૂંકા પ્રશ્નો, લાંબા પ્રશ્નો, પરિક્ષામાં પુછાઈ ગયેલા પ્રશ્નો તેમજ પરિક્ષામાં પુછાઈ શકે તેવા અનેક મુદ્દાસર પ્રશ્નો જોવા અમારી વેબસાઈટ પર રજીસ્ટર થાઓ અથવા અમારી App ફ્રી માં ડાઉનલોડ કરો.
The GSEB Books for class 10 are designed as per the syllabus followed Gujarat Secondary and Higher Secondary Education Board provides key detailed, and a through solutions to all the questions relating to the GSEB textbooks.
The purpose is to provide help to the students with their homework, preparing for the examinations and personal learning. These books are very helpful for the preparation of examination.
For more details about the GSEB books for Class 10, you can access the PDF which is as in the above given links for the same.