જવાબ : Height of cylinder = 20 cm And diameter = 7 cm and then radius = 3.5 cm Total surface area of article = lateral surface of cylinder
જવાબ :
જવાબ :
જવાબ : Radius of cylinder = Radius of hemisphere = 10.5 cm Height of cylinder = (14.5 10.5) cm = 4 cm Capacity = Volume of cylinder + Volume of hemisphere
જવાબ :
જવાબ :
જવાબ :
જવાબ :
જવાબ : Radius of cone = Radius of cylinder = 2.5 m Height of cylinder = 21 m Slant height of cone = 8 m Total surface area of the rocket = (curved surface area of cone + curved surface area of cylinder + area of base)
જવાબ :
જવાબ : Hence, the curved surface area of the tent = 1034 m^{2} Cost of canvas = Rs.(1034 × 80) = Rs. 82720
જવાબ :
જવાબ :
જવાબ :
જવાબ :
જવાબ :
જવાબ :
જવાબ :
જવાબ :
જવાબ :
જવાબ : Diameter of sphere = 18 cm
Radius of copper sphere =
Length of wire = 108 m = 10800 cm
But the volume of wire = Volume of sphere
Hence the diameter = 2r = (0.3 2) cm = 0.6 cm
જવાબ : Diameter of sphere = 42 cm Radius of sphere = Volume of sphere = Diameter of cylindrical wire = 2.8 cm Radius of cylindrical wire = Volume of cylindrical wire = Volume of cylindrical wire = volume of sphere Hence length of the wire 63 m.
જવાબ : Radius of sphere = 3 cm Volume of sphere = Radius of small sphere = Volume of small sphere = Let number of small balls be n Hence, the number of small balls = 1000.
જવાબ : Volume of sphere (when r = 1 cm) = = Volume of sphere (when r = 8 cm) = = Let the number of balls = n
જવાબ : Diameter of sphere = 21 cm Hence, radius of sphere = Volume of sphere = = Volume of cube = a^{3} = (1 1 1) Let number of cubes formed be n Volume of sphere = n Volume of cube Hence, number of cubes is 4851.
જવાબ : Volume of hemisphere of radius 9 cm Volume of circular cone (height = 72 cm) Volume of cone = Volume of hemisphere Hence radius of the base of the cone = 4.5 cm
જવાબ : External radius of shell = 12 cm and internal radius = 9 cm Volume of lead in the shell = Height of cylinder = 37 cm Volume of cylinder = Hence diameter of the base of the cylinder = 12 cm
જવાબ : Volume of third ball = Volume of spherical ball volume of 2 small balls
જવાબ : Radius of the cannon ball = 14 cm Volume of cannon ball = Radius of the cone = Let the height of cone be h cm Volume of cone = Hence, height of the cone = 35.84 cm
જવાબ : Radius of the sphere= Let the number of cones formed be n, then Hence, number of cones formed = 504
જવાબ : Inner radius of the bowl = 15 cm Volume of liquid in it = Radius of each cylindrical bottle = 2.5 cm and its height = 6 cm Volume of each cylindrical bottle Required number of bottles = Hence, bottles required = 60
જવાબ :
જવાબ : Internal radius = 3 cm and external radius = 5 cm Hence, height of the cone = 4 cm
જવાબ :
જવાબ : Radius of the cone = 12 cm and its height = 24 cm Volume of cone =
જવાબ :
જવાબ :
જવાબ :
જવાબ : Solution:
જવાબ : Solution:
જવાબ :
જવાબ :
જવાબ :
જવાબ : Height of cylinder= h_{1} = 6.5 cm Height of cone = h_{2} = 6.3 cm Radius of cylinder = radius of cone = radius of hemisphere = 3.5 cm Volume of solid = Volume of cylinder + Volume of cone + Volume of hemisphere
જવાબ : Diameter of spherical part of vessel = 21 cm
જવાબ : Radius of cylinder = 6 cm Height of cylinder = 8 cm Surface area of cylinder = 2 = 2× 6 × 8
જવાબ :
જવાબ :
જવાબ : Radius of cylinder = 6 cm Height of cylinder = 8 cm Volume of cylinder Volume of cone removed
જવાબ : Radius of cylinder r_{1}= 5cm And height of cylinder h_{1}= 9.8cm Radius of cone r_{2} = 2.1 cm And height of cone h_{2}= 4cm Volume of water left in tub = (volume of cylindrical tub – volume of solid)
જવાબ :
જવાબ :
જવાબ :
જવાબ :
The radii of two cylinders are in the ratio of 2 : 3 and their heights are in the ratio of 5 : 3. Calculate the ratio of their volumes.
જવાબ :
જવાબ :
જવાબ :
જવાબ :
જવાબ :
જવાબ :
જવાબ :
જવાબ :
જવાબ :
જવાબ :
જવાબ :
જવાબ :
જવાબ :
જવાબ :
જવાબ :
જવાબ :
Radius = 3 cm
1 |
Total Surface Area of Sphere |
A |
36π cm^{3} |
2 |
Volume of Sphere |
B |
27π cm^{2} |
3 |
Total Surface Area of Hemisphere |
C |
36π cm^{2} |
4 |
Volume of Sphere |
D |
27π cm^{3} |
જવાબ :
1-C, 2-A, 3-B, 4-D
Cuboid
1 |
Total Surface Area |
A |
2h(l+b) + lb |
2 |
Total Surface Area without lid |
B |
2h(l+b) |
3 |
Curved Surface Area |
C |
2(lb + bh + lh) |
4 |
Volume |
D |
Lbh |
Hide | Show
જવાબ :
1-C, 2-A, 3-B, 4-D
Radius = 3cm and Height of cone = 4cm
1 |
Total Surface Area |
A |
15π cm^{2} |
2 |
Slant Height |
B |
24π cm^{2} |
3 |
Curved Surface Area |
C |
12π cm^{3} |
4 |
Volume |
D |
5 cm |
જવાબ :
1-B, 2-D, 3-A, 4-C
Radius = 2cm and Height of cylinder = 6cm
1 |
Total Surface Area |
A |
42π cm^{3} |
2 |
Total Surface Area without lid |
B |
32π cm^{2} |
3 |
Curved Surface Area |
C |
28π cm^{2} |
4 |
Volume |
D |
24π cm^{2} |
જવાબ :
1-B, 2-C, 3-D, 4-A
Side of cube =4 cm
1 |
Total Surface Area |
A |
64 cm^{3} |
2 |
Total Surface Area without lid |
B |
64 cm^{2} |
3 |
Curved Surface Area |
C |
80 cm^{2} |
4 |
Volume |
D |
96 cm^{2} |
જવાબ :
1-D, 2-C, 3-B, 4-A
Length= 2 cm, Height= 3 cm and Bredth=4 cm
1 |
Total Surface Area |
A |
36cm^{2} |
2 |
Total Surface Area without lid |
B |
24cm^{3} |
3 |
Curved Surface Area |
C |
44cm^{2} |
4 |
Volume |
D |
52cm^{2} |
જવાબ :
1-D, 2-C, 3-A, 4-B
1 |
Total Surface Area of Sphere |
A |
3πr^{2} |
2 |
Volume of Sphere |
B |
23πr^{3} |
3 |
Total Surface Area of Hemisphere |
C |
43πr^{3} |
4 |
Volume of Sphere |
D |
4πr^{2} |
જવાબ :
1-D, 2-C, 3-A, 4-B
જવાબ :
1-A, 2-C, 3-B
Cylinder
1 |
Total Surface Area |
A |
πr^{2}h |
2 |
Total Surface Area without lid |
B |
2πr(h+r) |
3 |
Curved Surface Area |
C |
πr(2h+r) |
4 |
Volume |
D |
2πrh |
જવાબ :
1-B, 2-C, 3-D, 4-A
Cube
1 |
Total Surface Area |
A |
4s^{2} |
2 |
Total Surface Area without lid |
B |
6s^{2} |
3 |
Curved Surface Area |
C |
s^{3} |
4 |
Volume |
D |
5s^{2} |
જવાબ :
1-B, 2-D, 3-A, 4-C
Math
Chapter 13 : Surface Areas and Volumes
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