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CBSE Solutions for Class 10 English

GSEB std 10 science solution for Gujarati check Subject Chapters Wise::

A wooden article was made by scooping out a hemisphere from each end of a cylinder, as shown in the figure. If the height of the cylinder is 20 cm and its base is of diameter 7 cm, Calculate the total surface area of the article when it is ready.

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જવાબ : Height of cylinder = 20 cm And diameter = 7 cm and then radius = 3.5 cm Total surface area of article  = lateral surface of cylinder


A medicine capsule is in the shape of a cylinder with two hemispheres stuck to each of its ends. The length of the entire capsule is 14 mm and the diameter of the capsule is 5 mm. Calculate its surface area.

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A toy is in the form of a cylinder with hemispherical ends. If the whole length of the toy is 90 cm and its diameter is 42 cm, calculate the cost of painting the toy at the rate of 70 paise per sq cm.

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A vessel is in the form of a hemispherical bowl surmounted by a hollow cylinder. The diameter of the hemisphere is 21 cm and the total height of the vessel is 14.5 cm. Calculate its capacity.

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જવાબ : Radius of cylinder = Radius of hemisphere = 10.5 cm Height of cylinder = (14.5 10.5) cm = 4 cm Capacity = Volume of cylinder + Volume of hemisphere


A cylindrical container of radius 6 cm and height 15 cm is filled with ice-cream. The whole ice-cream has to be distributed to 10 children in equal cones with hemispherical tops. If the height of the conical portion is 4 times the radius of its base, calculate the radius of the ice-cream cone.

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A toy is in the shape of a cone mounted on a hemisphere of same base radius. If the volume of the toy is 231 cm3 and its diameter is 7 cm, calculate the height of the toy.

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A toy is in the form of a cone mounted on a hemisphere of common base radius 7 cm. The total height of the toy is 31 cm. Calculate the total surface area of the toy.

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A solid is in the shape of a cone surmounted on a hemisphere, the radius of each of them being 3.5 cm and the total height of the solid is 9.5 cm. Calculate the volume of the solid.

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A rocket is in the form of a circular cylinder closed at the lower end and a cone of the same radius is attached to the top. The radius of the cylinder is 2.5m, its height of 21 m and the slant height of the cone is 8 m. Find the total surface area of the rocket.

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જવાબ : Radius of cone = Radius  of cylinder = 2.5 m Height of cylinder = 21 m Slant height of cone = 8 m Total surface area of the rocket = (curved surface area of cone                                                               + curved surface area of cylinder + area of base)


A circus tent is cylindrical to a height of 3 m and conical above it. If its base radius is 52.5 m and the slant height of the conical portion is 53 m, calculate the area of canvas needed to make the tent.

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A tent is in the shape of a right circular cylinder up to a height of 3 m and conical above it. The total height of the tent is 13.5 m and the radius of its base is 14 m. Calculate the cost of cloth required to make the tent at the rate of Rs.80 per square meter.

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જવાબ : Hence, the curved surface area of the tent = 1034 m2 Cost of canvas = Rs.(1034 × 80) = Rs. 82720


A military tent of height 8.25 m is in the form of a right circular cylinder of base diameter 30 m and height 5.5 in surmounted by a right circular cone of same base radius. Calculate the length of canvas used in making the tent, if the breadth of the canvas is 1.5 m.

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The surface area of a sphere is 2464 cm2. If its radius be doubled, find the surface area of the new sphere.

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If the total surface area of a solid hemisphere is 462 cm2, calculate its volume.

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Two cubes each of volume 27 cm' are joined end to end to form a solid. Calculate the surface area of the resulting cuboid.

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The volume of a hemisphere is 2425.5 cm3 . Calculate its surface area.

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The sum of the radius of the base and the height of a solid cylinder is 37 metres. If the total surface area of the cylinder be 1628 sq metres, calculate its volume.

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The slant height of a conical mountain is 2.5 km and the area of its base is 1.54 km2. Calculate the height of the mountain.

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If the volumes of two cones are in the ratio of 1: 4 and their diameters are in the ratio of 4 : 5, calculate the ratio of their heights.

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A 5-m-wide cloth is used to make a conical tent of base diameter 14 m and height 24 m. Calculate the cost of cloth used at the rate of Rs. 25 per metre.

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The diameter of a copper sphere is 18 cm. It is melted and drawn into a long wire of uniform cross section. If the length of the wire is 108 m, calculate its diameter.

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જવાબ : Diameter of sphere = 18 cm Radius of copper sphere = R-s-aggarwal-and-v-aggarwal Solutions Cbse Class 10 Mathematics Chapter - Volume And Surface Areas Of SolidsR-s-aggarwal-and-v-aggarwal Solutions Cbse Class 10 Mathematics Chapter - Volume And Surface Areas Of Solids Length of wire = 108 m = 10800 cm                           R-s-aggarwal-and-v-aggarwal Solutions Cbse Class 10 Mathematics Chapter - Volume And Surface Areas Of Solids But the volume of wire = Volume of sphere          R-s-aggarwal-and-v-aggarwal Solutions Cbse Class 10 Mathematics Chapter - Volume And Surface Areas Of Solids
  Hence the diameter = 2r = (0.3 2) cm = 0.6 cm


The diameter of a sphere is 42 cm. It is melted and drawn into a cylindrical wire of diameter 2.8 cm. Calculate the length of the wire.

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જવાબ : Diameter of sphere = 42 cm Radius of sphere = R-s-aggarwal-and-v-aggarwal Solutions Cbse Class 10 Mathematics Chapter - Volume And Surface Areas Of Solids Volume of sphere = R-s-aggarwal-and-v-aggarwal Solutions Cbse Class 10 Mathematics Chapter - Volume And Surface Areas Of Solids Diameter of cylindrical wire = 2.8 cm Radius of cylindrical wire = R-s-aggarwal-and-v-aggarwal Solutions Cbse Class 10 Mathematics Chapter - Volume And Surface Areas Of Solids Volume of cylindrical wire = R-s-aggarwal-and-v-aggarwal Solutions Cbse Class 10 Mathematics Chapter - Volume And Surface Areas Of Solids                                    R-s-aggarwal-and-v-aggarwal Solutions Cbse Class 10 Mathematics Chapter - Volume And Surface Areas Of Solids Volume of cylindrical wire = volume of sphere R-s-aggarwal-and-v-aggarwal Solutions Cbse Class 10 Mathematics Chapter - Volume And Surface Areas Of Solids Hence length of the wire 63 m.


A solid sphere of radius 3cm is melted and then cast into small spherical balls, each of diameter 0.6 cm. Calculate the number of small balls so obtained.

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જવાબ : Radius of sphere = 3 cm Volume of sphere = R-s-aggarwal-and-v-aggarwal Solutions Cbse Class 10 Mathematics Chapter - Volume And Surface Areas Of Solids Radius of small sphere = R-s-aggarwal-and-v-aggarwal Solutions Cbse Class 10 Mathematics Chapter - Volume And Surface Areas Of Solids Volume of small sphere = R-s-aggarwal-and-v-aggarwal Solutions Cbse Class 10 Mathematics Chapter - Volume And Surface Areas Of Solids                                  R-s-aggarwal-and-v-aggarwal Solutions Cbse Class 10 Mathematics Chapter - Volume And Surface Areas Of Solids Let number of small balls be n R-s-aggarwal-and-v-aggarwal Solutions Cbse Class 10 Mathematics Chapter - Volume And Surface Areas Of Solids Hence, the number of small balls = 1000.


How many lead balls, each of radius 1 cm, can be made from a sphere of radius 8 cm?

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જવાબ : Volume of sphere (when r = 1 cm) = R-s-aggarwal-and-v-aggarwal Solutions Cbse Class 10 Mathematics Chapter - Volume And Surface Areas Of Solids = R-s-aggarwal-and-v-aggarwal Solutions Cbse Class 10 Mathematics Chapter - Volume And Surface Areas Of Solids Volume of sphere (when r = 8 cm) = R-s-aggarwal-and-v-aggarwal Solutions Cbse Class 10 Mathematics Chapter - Volume And Surface Areas Of Solids = R-s-aggarwal-and-v-aggarwal Solutions Cbse Class 10 Mathematics Chapter - Volume And Surface Areas Of Solids Let the number of balls = n R-s-aggarwal-and-v-aggarwal Solutions Cbse Class 10 Mathematics Chapter - Volume And Surface Areas Of Solids


A spherical ball of diameter 21 cm is melted and recast into cubes, each of side 1 cm. Calculate the number of cubes so formed.

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જવાબ : Diameter of sphere = 21 cm Hence, radius of sphere = R-s-aggarwal-and-v-aggarwal Solutions Cbse Class 10 Mathematics Chapter - Volume And Surface Areas Of Solids Volume of sphere = R-s-aggarwal-and-v-aggarwal Solutions Cbse Class 10 Mathematics Chapter - Volume And Surface Areas Of Solids = R-s-aggarwal-and-v-aggarwal Solutions Cbse Class 10 Mathematics Chapter - Volume And Surface Areas Of Solids Volume of cube = a3 = (1 1 1) R-s-aggarwal-and-v-aggarwal Solutions Cbse Class 10 Mathematics Chapter - Volume And Surface Areas Of Solids Let number of cubes formed be n R-s-aggarwal-and-v-aggarwal Solutions Cbse Class 10 Mathematics Chapter - Volume And Surface Areas Of SolidsVolume of sphere = n Volume of cube R-s-aggarwal-and-v-aggarwal Solutions Cbse Class 10 Mathematics Chapter - Volume And Surface Areas Of Solids Hence, number of cubes is 4851.


A hemisphere of lead of radius 9 cm is cast intoa right circular cone of height 72 cm. Calculate the radius of the base of the cone.

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જવાબ : Volume of hemisphere of radius 9 cm                                         R-s-aggarwal-and-v-aggarwal Solutions Cbse Class 10 Mathematics Chapter - Volume And Surface Areas Of Solids Volume of circular cone (height = 72 cm)                                        R-s-aggarwal-and-v-aggarwal Solutions Cbse Class 10 Mathematics Chapter - Volume And Surface Areas Of Solids Volume of cone = Volume of hemisphere R-s-aggarwal-and-v-aggarwal Solutions Cbse Class 10 Mathematics Chapter - Volume And Surface Areas Of Solids Hence radius of the base of the cone = 4.5 cm


A spherical shell of lead whose external and internal diameters are respectively 24 cm and 18 cm, is melted ad recast into a right circular cylinder 37 cm high. Calculate the diameter of the base of the cylinder.

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જવાબ : External radius of shell = 12 cm and internal radius = 9 cm Volume of lead in the shell = R-s-aggarwal-and-v-aggarwal Solutions Cbse Class 10 Mathematics Chapter - Volume And Surface Areas Of Solids  Height of cylinder = 37 cm Volume of cylinder = R-s-aggarwal-and-v-aggarwal Solutions Cbse Class 10 Mathematics Chapter - Volume And Surface Areas Of Solids R-s-aggarwal-and-v-aggarwal Solutions Cbse Class 10 Mathematics Chapter - Volume And Surface Areas Of Solids Hence diameter of the base of the cylinder = 12 cm


A spherical ball of radius 3 cm is melted and recast into three spherical balls. The radii of two of these balls are 1.5cm and 2 cm. Calculate the radius of third ball.

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જવાબ :  Volume of third ball = Volume of spherical ball volume of 2 small balls            R-s-aggarwal-and-v-aggarwal Solutions Cbse Class 10 Mathematics Chapter - Volume And Surface Areas Of Solids


A spherical cannon ball 28 cm in diameter is melted and recast into right circular conical mould, base of which is 35 cm in diameter. Calculate the height of the cone.

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જવાબ : Radius of the cannon ball = 14 cm Volume of cannon ball = R-s-aggarwal-and-v-aggarwal Solutions Cbse Class 10 Mathematics Chapter - Volume And Surface Areas Of Solids Radius of the cone = R-s-aggarwal-and-v-aggarwal Solutions Cbse Class 10 Mathematics Chapter - Volume And Surface Areas Of Solids Let the height of cone be h cm R-s-aggarwal-and-v-aggarwal Solutions Cbse Class 10 Mathematics Chapter - Volume And Surface Areas Of SolidsVolume of cone = R-s-aggarwal-and-v-aggarwal Solutions Cbse Class 10 Mathematics Chapter - Volume And Surface Areas Of Solids             R-s-aggarwal-and-v-aggarwal Solutions Cbse Class 10 Mathematics Chapter - Volume And Surface Areas Of Solids             Hence, height of the cone = 35.84 cm


A solid metallic sphere of diameter 21 cm is melted and recast into a number of smaller cones, each of diameter 3.5 cm and height 3 cm. Calculate the number of cones so formed.

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જવાબ : Radius of the sphere= R-s-aggarwal-and-v-aggarwal Solutions Cbse Class 10 Mathematics Chapter - Volume And Surface Areas Of Solids R-s-aggarwal-and-v-aggarwal Solutions Cbse Class 10 Mathematics Chapter - Volume And Surface Areas Of Solids Let the number of cones formed be n, then                R-s-aggarwal-and-v-aggarwal Solutions Cbse Class 10 Mathematics Chapter - Volume And Surface Areas Of Solids             Hence, number of cones formed = 504


A hemispherical bowl of internal diameter 30cm contains some liquid. This liquid is to be filled into cylindrical shaped bottles each of diameter 5 cm and height 6 cm. Calculate the number of bottles necessary to empty the bowl.

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જવાબ : Inner radius of the bowl = 15 cm Volume of liquid in it = R-s-aggarwal-and-v-aggarwal Solutions Cbse Class 10 Mathematics Chapter - Volume And Surface Areas Of Solids Radius of each cylindrical bottle = 2.5 cm and its height = 6 cm Volume of each cylindrical bottle                                        R-s-aggarwal-and-v-aggarwal Solutions Cbse Class 10 Mathematics Chapter - Volume And Surface Areas Of Solids Required number of bottles = R-s-aggarwal-and-v-aggarwal Solutions Cbse Class 10 Mathematics Chapter - Volume And Surface Areas Of Solids                                        R-s-aggarwal-and-v-aggarwal Solutions Cbse Class 10 Mathematics Chapter - Volume And Surface Areas Of Solids    Hence, bottles required = 60


A copper rod of diameter 2 cm and length 10 cm is drawn into a wire of uniform thickness and length 10 m. Calculate the Thickness of the wire.

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જવાબ : R-s-aggarwal-and-v-aggarwal Solutions Cbse Class 10 Mathematics Chapter - Volume And Surface Areas Of Solids


The internal and external diameters of a hollow hemispherical shell are 6 cm and 10 cm respectively. It is melted and recast into a solid cone of base diameter 14 cm. Calculate the height of the cone so formed.

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જવાબ : Internal radius = 3 cm and external radius = 5 cm R-s-aggarwal-and-v-aggarwal Solutions Cbse Class 10 Mathematics Chapter - Volume And Surface Areas Of Solids Hence, height of the cone = 4 cm


The radii of internal and external surfaces of a hollow spherical shell are 3 cm and 5 cm respectively. It is melted and recast into a solid cylinder of diameter 14 cm. Calculate the height of the cylinder.

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જવાબ : R-s-aggarwal-and-v-aggarwal Solutions Cbse Class 10 Mathematics Chapter - Volume And Surface Areas Of Solids


A solid metal cone with radius of base 12 cm and height 24 cm is melted to form solid spherical balls of diameter 6 cm each. Calculate the number of balls thus formed.

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જવાબ : Radius of the cone = 12 cm and its height = 24 cm Volume of cone = R-s-aggarwal-and-v-aggarwal Solutions Cbse Class 10 Mathematics Chapter - Volume And Surface Areas Of Solids                       R-s-aggarwal-and-v-aggarwal Solutions Cbse Class 10 Mathematics Chapter - Volume And Surface Areas Of Solids R-s-aggarwal-and-v-aggarwal Solutions Cbse Class 10 Mathematics Chapter - Volume And Surface Areas Of Solids


Metallic spheres of radii 6 cm, 8 cm and 10 cm respectively are melted to form a single solid sphere. Calculate the radius of the resulting sphere.

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જવાબ : R-s-aggarwal-and-v-aggarwal Solutions Cbse Class 10 Mathematics Chapter - Volume And Surface Areas Of Solids


A cone of height 20 cm and radius of base 5 cm is made up of modelling clay. A child reshapes it in the form of a sphere. Calculate the diameter of the sphere.

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જવાબ : R-s-aggarwal-and-v-aggarwal Solutions Cbse Class 10 Mathematics Chapter - Volume And Surface Areas Of Solids


The dimensions of a metallic cuboid are 100 cm x 80 cm x 64 cm. It is melted and recast into a cube. Calculate the surface area of the cube.

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જવાબ : R-s-aggarwal-and-v-aggarwal Solutions Cbse Class 10 Mathematics Chapter - Volume And Surface Areas Of Solids


A wooden toy is in the shape of a cone mounted on a cylinder, as shown in the figure. The total height of the toy is 26 cm, while the height of the conical part is 6 cm. The diameter of the base of the conical part is 5 cm and that of the cylindrical part is 4 cm. The conical part and the cylindrical part are respectively painted red and white. Calculate the area to be painted by each of these colours.

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જવાબ : R-s-aggarwal-and-v-aggarwal Solutions Cbse Class 10 Mathematics Chapter - Volume And Surface Areas Of Solids Solution: R-s-aggarwal-and-v-aggarwal Solutions Cbse Class 10 Mathematics Chapter - Volume And Surface Areas Of Solids


The inner diameter of a glass is 7 cm and it has a raised portion in the bottom in the shape of a hemisphere, as shown in the figure. If the height of the glass is 16 cm, calculate the apparent capacity and the actual capacity of the glass.

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જવાબ : R-s-aggarwal-and-v-aggarwal Solutions Cbse Class 10 Mathematics Chapter - Volume And Surface Areas Of Solids Solution: R-s-aggarwal-and-v-aggarwal Solutions Cbse Class 10 Mathematics Chapter - Volume And Surface Areas Of Solids


A toy is in the shape of a right circular cylinder with a hemisphere on one end and a cone on the other. The radius and height of the cylindrical part are 5 cm and 13 cm respectively. The radii of the hemispherical and the conical parts are the same as that of the cylindrical part. Calculate the surface area of the toy, if the total height of the toy is 30 cm.

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જવાબ : R-s-aggarwal-and-v-aggarwal Solutions Cbse Class 10 Mathematics Chapter - Volume And Surface Areas Of Solids


A cubical block of side 10 cm is surmounted by a hemisphere. What is the largest diameter that the hemisphere can have? Calculate the cost of painting the total surface area of the solid so formed, at the rate of Rs.5 per 100 sq cm. [Use π = 3.14.]

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જવાબ : R-s-aggarwal-and-v-aggarwal Solutions Cbse Class 10 Mathematics Chapter - Volume And Surface Areas Of Solids


From a cubical piece of wood of side 21 cm, a hemisphere is carved out in such a way that the diameter of the hemisphere is equal to the side of the cubical piece. Calculate the surface area and volume of the remaining piece.

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જવાબ : R-s-aggarwal-and-v-aggarwal Solutions Cbse Class 10 Mathematics Chapter - Volume And Surface Areas Of Solids


The adjoining figure represents a solid consisting of a cylinder surmounted by a cone at one end and a hemisphere at the other. Calculate the volume of the solid.

            R-s-aggarwal-and-v-aggarwal Solutions Cbse Class 10 Mathematics Chapter - Volume And Surface Areas Of Solids

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જવાબ :  R-s-aggarwal-and-v-aggarwal Solutions Cbse Class 10 Mathematics Chapter - Volume And Surface Areas Of Solids Height of cylinder= h1 = 6.5 cm Height of cone =  h2 = 6.3 cm Radius of cylinder = radius of cone = radius of hemisphere =  3.5 cm Volume of solid = Volume of cylinder + Volume of cone + Volume of hemisphere                        R-s-aggarwal-and-v-aggarwal Solutions Cbse Class 10 Mathematics Chapter - Volume And Surface Areas Of Solids


A spherical glass vessel has a cylindrical neck 7 cm long and 4 cm in diameter. The diameter of the spherical part is 21 cm. Calculate the quantity of water it can hold.

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જવાબ : R-s-aggarwal-and-v-aggarwal Solutions Cbse Class 10 Mathematics Chapter - Volume And Surface Areas Of Solids Diameter of spherical part of vessel = 21 cm R-s-aggarwal-and-v-aggarwal Solutions Cbse Class 10 Mathematics Chapter - Volume And Surface Areas Of Solids


From a solid cylinder whose height is 8 cm and radius 6 cm, a conical cavity of height 8cm and of base radius 6 cm, is hollowed out. Find the total surface area of the remaining solid. Take π = 3.14

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જવાબ : Radius of cylinder = 6 cm Height of cylinder = 8 cm R-s-aggarwal-and-v-aggarwal Solutions Cbse Class 10 Mathematics Chapter - Volume And Surface Areas Of Solids  Surface area of cylinder = 2R-s-aggarwal-and-v-aggarwal Solutions Cbse Class 10 Mathematics Chapter - Volume And Surface Areas Of Solids = 2R-s-aggarwal-and-v-aggarwal Solutions Cbse Class 10 Mathematics Chapter - Volume And Surface Areas Of Solids× 6 × 8 R-s-aggarwal-and-v-aggarwal Solutions Cbse Class 10 Mathematics Chapter - Volume And Surface Areas Of Solids R-s-aggarwal-and-v-aggarwal Solutions Cbse Class 10 Mathematics Chapter - Volume And Surface Areas Of Solids


From a solid cylinder of height 14 cm and base diameter 7 cm, two equal conical holes each of radius 2.1 cm and height 4 cm are cut off. Calculate the volume of the remaining solid.

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જવાબ : R-s-aggarwal-and-v-aggarwal Solutions Cbse Class 10 Mathematics Chapter - Volume And Surface Areas Of Solids


From a solid cylinder of height 2.8 cm and diameter 4.2 cm, a conical cavity of the same height and same diameter is hollowed out. Calculate the total surface area of the remaining solid.

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જવાબ : R-s-aggarwal-and-v-aggarwal Solutions Cbse Class 10 Mathematics Chapter - Volume And Surface Areas Of Solids  


From a solid cylinder whose height is 8 cm and radius 6 cm, a conical cavity of height 8cm and of base radius 6 cm, is hollowed out. Find the volume of the remaining solid. Take π = 3.14

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જવાબ : Radius of cylinder = 6 cm Height of cylinder = 8 cm R-s-aggarwal-and-v-aggarwal Solutions Cbse Class 10 Mathematics Chapter - Volume And Surface Areas Of Solids  Volume of cylinder               R-s-aggarwal-and-v-aggarwal Solutions Cbse Class 10 Mathematics Chapter - Volume And Surface Areas Of Solids Volume of cone removed               R-s-aggarwal-and-v-aggarwal Solutions Cbse Class 10 Mathematics Chapter - Volume And Surface Areas Of Solids


A solid is in the form of a right circular cone mounted on a hemisphere. The radius of the hemisphere is 21. cm and the height of the cone is 4 cm. The solid is placed in a cylindrical tub full of water in such a way that the whole solid is submerged in water. If the radius of the cylinder is 5 cm and its height is 9.8 cm, Calculate the volume of the water left in the tub.

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જવાબ : R-s-aggarwal-and-v-aggarwal Solutions Cbse Class 10 Mathematics Chapter - Volume And Surface Areas Of Solids Radius of cylinder  r1= 5cm And height of cylinder h1= 9.8cm Radius of cone r2 = 2.1 cm And height of cone h2= 4cm Volume of water left in tub = (volume of cylindrical tub – volume of solid)                          R-s-aggarwal-and-v-aggarwal Solutions Cbse Class 10 Mathematics Chapter - Volume And Surface Areas Of Solids


66 cubic cm of silver is drawn into a wire 1 mm in diameter. Find the length of the wire in metres.

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The volumes of two cubes are in the ratio 8 : 27. Calculate the ratio of their surface areas.

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The volume of a right circular cylinder with its height equal to the radius is 253 . Calculate the height of the cylinder.

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The ratio between the radius of the base and the height of a cylinder is 2 : 3. If the volume of the cylinder is 12936 cm3, calculate the radius of the base of the cylinder.

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The radii of two cylinders are in the ratio of 2 : 3 and their heights are in the ratio of 5 : 3. Calculate the ratio of their volumes.

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The volume of a cube is 729 cm3. Calculate its surface area.

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A river 1.5 m deep and 36 m wide is flowing at the rate of 3.5 km/hr. Find the amount of water (in cubic metres) that runs into the sea per minute.

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Calculate cubes of 10 cm edge can be put in a cubical box of 1 m edge?

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Three cubes of iron whose edges are 6 cm, 8 cm and 10 cm respectively are melted and formed into a single cube. Calculate the edge of the new cube formed.

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Five identical cubes, each of edge 5 cm, are placed adjacent to each other. Calculate the volume of the resulting cuboid.

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A hemisphere of lead of radius 6 cm is cast into a right circular cone of height 75 cm. Calculate the radius of the base of the cone.

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A metallic cone of radius 12 cm and height 24 cm is melted and made into spheres of radius 2 cm each. Find the no. of spheres are formed.

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Find the no. of lead shots each 3 mm in diameter can be made from a cuboid of dimensions 9 cm x 11 cm x 12 cm

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A solid metallic sphere of radius 8 cm is melted and recast into spherical balls each of radius 2 cm. Calculate the number of spherical balls obtained.

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The surface areas of two spheres are in the ratio of 4 : 25. Calculate the ratio of their volumes.

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The curved surface area of a sphere is 5544 cm3. Find its volume.

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The volume of a sphere is 4851 cm3. Calculate its curved surface area.

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A right cylindrical vessel is full of water. Find the no. of right cones having the same radius and height as those of the right cylinder will be needed to store that water.

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A cylinder with base radius 8 cm and height 2 cm is melted to form a cone of height 6 cm. Find the radius of the base of the cone.

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If the area of the base of a right circular cone is 3850 cm2 and its height is 84 cm, calculate the slant height of the cone.

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There are No Content Availble For this Chapter

Radius = 3 cm

1

Total Surface Area of Sphere

A

36π cm3

2

Volume of Sphere

B

27π cm2

3

Total Surface Area of Hemisphere

C

36π cm2

4

Volume of Sphere

D

27π cm3

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જવાબ :

1-C, 2-A, 3-B, 4-D

Cuboid

1

Total Surface Area

A

2h(l+b) + lb

2

Total Surface Area without lid

B

2h(l+b)

3

Curved Surface Area

C

2(lb + bh + lh)

4

Volume

D

Lbh

 

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જવાબ :

1-C, 2-A, 3-B, 4-D

Radius = 3cm and Height of cone = 4cm

1

Total Surface Area

A

15π cm2

2

Slant Height

B

24π cm2

3

Curved Surface Area

C

12π cm3

4

Volume

D

5 cm

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જવાબ :

1-B, 2-D, 3-A, 4-C

Radius = 2cm and Height of cylinder = 6cm             

1

Total Surface Area

A

42π cm3

2

Total Surface Area without lid

B

32π cm2

3

Curved Surface Area

C

28π cm2

4

Volume

D

24π cm2

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જવાબ :

1-B, 2-C, 3-D, 4-A

Side of cube =4 cm

1

Total Surface Area

A

64 cm3

2

Total Surface Area without lid

B

64 cm2

3

Curved Surface Area

C

80 cm2

4

Volume

D

96 cm2

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જવાબ :

1-D, 2-C, 3-B, 4-A

Length= 2 cm, Height= 3 cm and Bredth=4 cm

1

Total Surface Area

A

36cm2

2

Total Surface Area without lid

B

24cm3

3

Curved Surface Area

C

44cm2

4

Volume

D

52cm2

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જવાબ :

1-D, 2-C, 3-A, 4-B

1

Total Surface Area of Sphere

A

3πr2

2

Volume of Sphere

B

23πr3

3

Total Surface Area of Hemisphere

C

43πr3

4

Volume of Sphere

D

4πr2

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જવાબ :

1-D, 2-C, 3-A, 4-B

Cone

1

Total Surface Area

A

πr(r+l)

2

Volume

B

πrl

3

Curved Surface Area

C

13 πr2h

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જવાબ :

1-A, 2-C, 3-B

Cylinder

1

Total Surface Area

A

πr2h

2

Total Surface Area without lid

B

2πr(h+r)

3

Curved Surface Area

C

πr(2h+r)

4

Volume

D

2πrh

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જવાબ :

1-B, 2-C, 3-D, 4-A

Cube

1

Total Surface Area

A

4s2

2

Total Surface Area without lid

B

6s2

3

Curved Surface Area

C

s3

4

Volume

D

5s2

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જવાબ :

1-B, 2-D, 3-A, 4-C

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Surface Areas and Volumes

Chapter 13 : Surface Areas and Volumes

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આ પ્રકરણને લગતા વિવિધ એનિમેશન વિડીયો, હેતુલક્ષી પ્રશ્નો, ટૂંકા પ્રશ્નો, લાંબા પ્રશ્નો, પરિક્ષામાં પુછાઈ ગયેલા પ્રશ્નો તેમજ પરિક્ષામાં પુછાઈ શકે તેવા અનેક મુદ્દાસર પ્રશ્નો જોવા અમારી વેબસાઈટ પર રજીસ્ટર થાઓ અથવા અમારી App ફ્રી માં ડાઉનલોડ કરો.

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