# CBSE Solutions for Class 10 English

#### GSEB std 10 science solution for Gujarati check Subject Chapters Wise::

The mean of 50 numbers is 18, the new mean will be …. if each observation is increased by 4  ( 22/24/20)

જવાબ : 24

The sum of deviations of a set of values {a,b,c,d,e,f,g.h.i……} n items  measured from 26 is  -10 and the sum of deviations of the values from 20 is 50. The value of n is …(10/12/9) And mean of the items is ……. ( 19/18/17/25)

જવાબ : 25

For a given data with 110 observations the ‘less than ogive’ and the ‘more then ogive’ intersect at (18, 20). The median of the data is …… (18/20/19)

જવાબ : 18

The curve drawn by taking upper limits along x-axis and cumulative frequency along y-axis is ……….( less than ogive /more than ogive)

જવાબ : less than ogive curve

The mean of five numbers is 40. If one number is excluded, their mean becomes 28. The excluded number is……. (68 / 88)

જવાબ : 88

While computing mean of grouped data, we assume that the frequencies are centred at the ____________ of the classes

જવાબ : class-marks

For drawing a frequency polygon of a continuous frequency distribution, we plot the Points whose ordinates are the frequencies of the respective classes and abscissae are respectively :

જવાબ : class marks of the classes

Find the mean of 32 numbers given mean of ten of them is 12 and the mean of other 20 is 9. And last 2 number is 10

જવાબ : 10

The median and mean of the first 10 natural numbers.

જવાબ : 5.5,5.5

Anand says that the median of 3, 14, 19, 20, 11 is 19. What doesn’t the Anand understand about finding the median?

જવાબ : The dataset should be ascending order

The following observations are arranged in ascending order :
20, 23, 42, 53, x, x + 2, 70, 75, 82, 96
If the median is 63, find the value of x.

જવાબ : 62

The mean of 20 observations was 60. It was detected on rechecking that the value of 125 was wrongly copied as 25 for computation of mean. Find the correct mean

જવાબ : 65

Compute the Median for the given data

 Class –interval 100-110 110-120 120-130 130-140 140-150 150-160 Frequency 6 35 48 72 100 4

જવાબ : 136.11

In a continuous frequency distribution, the median of the data is 21. If each observation is increased by 5, then find the new median. (2015)

જવાબ : New median = 21 + 5 = 26

From the following frequency distribution, find the median class: (2015)

 Cost of living index No. of weeks 1400- 1550 8 1550-1700 15 1700-1850 21 1850-2000 8

જવાબ : Median class 1700 – 1850.

For one term, absentee record of students is given below. If mean is 15.5, then the missing frequencies x and y are:

 Number of days 0-5 5-10 10-15 15-20 20-25 25-30 30-35 35-40 TOTAL Total Number of students 15 16 x 8 y 8 6 4 70

જવાબ : x = 7 and y = 6

The Median when it is given that mode and mean are 8 and 9 respectively, is:

જવાબ : 8.67

If the arithmetic mean of x, x + 3, x + 6, x + 9 and x + 12 is 10, then x = ?

જવાબ : 4

If the mean of first n natural numbers is 5n/9, then n =?

જવાબ : 9

In a small scale industry, salaries of employees are given in the following distribution table:

 Salary (in Rs.) 4000 - 5000 5000-6000 6000-7000 7000-8000 8000-9000 9000-10000 Number of employees 20 60 100 50 80 90
Then the mean salary of the employee is:

જવાબ : Rs. 7450

In a hospital, weights of new born babies were recorded, for one month. Data is as shown:

 Weight of new born baby (in kg) 1.4 – 1.8 1.8 – 2.2 2.2 – 2.6 2.6 – 3.0 No of babies 3 15 6 1
Then the median weight is:

જવાબ : 2.05 kg

If 35 is removed from the data, 30, 34, 35, 36, 37, 38, 39, 40 then the median increases by ________

જવાબ : 0.5

The Median when it is given that mode and mean are 8 and 9 respectively, is

જવાબ : 8.67

The cumulative frequency table is useful in determining the ____________?

જવાબ : Median

If the mean of 4 numbers, 2,6,7 and a is 15 and also the mean of other 5 numbers, 6, 18 , 1, a, b is 50. What is the value of b?

જવાબ : The value of b = 180

The daily minimum steps climbed by a man during a week were as under:

 Monday Tuesday Wednesday Thursday Friday Saturday 35 30 27 32 23 28

Find the mean steps

જવાબ : Mean = 29.17

A student scored the following marks in 6 subjects:

30, 19, 25, 30, 27, 30

Find his modal score.

જવાબ : The mode is 30.

Find the mode of the following items.

0, 5, 5, 1, 6, 4, 3, 0, 2, 5, 5, 6

જવાબ : the mode is = 5

While checking the value of 20 observations, it was noted that 125 was wrongly noted as 25 while calculating the mean and then the mean was 60. Find the correct mean.

જવાબ : 65

Find the value of y from the following observations if these are already arranged in ascending order. The Median is 63.

20, 24, 42, y , y +2, 73, 75, 80, 99

જવાબ : 61

Show that the mode of the series obtained by combining the two series S1 and Sgiven below is different from that of Sand S2 taken separately: (2015)
S1 : 3, 5, 8, 8, 9, 12, 13, 9, 9
S2 : 7, 4, 7, 8, 7, 8, 13

જવાબ : In S1 : Number 9 occurs 3 times
Mode of S1 Series = 9
In S2 : Number 7 occurs 3 times

Mode of S, Series = 7
After combination:
In S
1 & S2 : No. 8 occurs 4 times
Mode of S1 & S2 taken combined = 8
So, mode of S1 & S2 combined is different from that of S1 & S2 taken separately.

Find the median of the data using an empirical formula, when it is given that mode = 35.3 and mean = 30.5. (2014)

જવાબ : Mode = 3(Median) – 2(Mean)
35.3 = 3(X) – 2(30.5)
35.3 = 3(X) – 61
96.3 = 3 X
Median = 32.1

Find the mean of the 32 numbers, such that if the mean of 10 of them is 15 and the mean of 20 of them is 11. The last two numbers are 10.

જવાબ : 390 /32

Find the mean of the first 11 natural numbers.

જવાબ : 6

Find the mean of the following data. (2012)

 Class Frequency Less than 20 15 Less than 40 37 Less than 60 74 Less than 80 99 Less than 100 120

જવાબ :

= 52.5

The following table gives the literacy rate (in %) in 40 cities. Find the mean literacy rate: (2012)

 Literacy rate No. of cities 45 – 55 4 55 – 65 11 65 – 75 12 75 – 85 9 85 – 95 4

જવાબ :

The following table gives the daily income of 50 workers of a factory. Draw both types (“less than type” and “greater than type”) ogives. (2015)

 Daily Income No. of workers 100-120 12 120-140 14 140-160 8 160-180 6 180-200 10

જવાબ :

In the table below, heart-beats of 30 women are recorded. If mean of the data is 76, find the missing frequencies x and y. (2014)

 No. of heart beats No. of women 65-68 x 68-71 4 71-74 3 74-77 7 77-80 8 80-83 4 83-86 y

જવાબ :

1978 + 66.5x + 84.5y = 2280
1978 + 66.5x + 84.5(4 – x) = 2280 … [From (A)
1978 + 66.5x + 338 – 84.5x = 2280
1978 + 338 – 2280 = 84.5x – 66.5x
36 = 18x x = 2
From (A), y = 4 – x = 4 – 2 = 2
x = 2, y = 2

The mean of the following frequency distribution is 62.8 and the sum of frequencies is 50. Find the missing frequencies f1 and f2: (2013)

 Classes Frequencies 0 – 20 5 20 – 40 f1 40 – 60 20 60 – 80 f2 80 – 100 7 100 – 120 8

જવાબ :

2060 + 30f1 + 70f2 = 3140
30f1 + 70f2 = 3140 – 2060 = 1080
3f1 + 7f2 = 108 …[Dividing by 10
3f1 + 7(20 – f1) = 108 … [From (A)
3f1 + 140 – 7f1 = 108
-4f1 = 108 – 140 = -32 .
f1 = 8
Putting the value of f1 into (A), we get
f2 = 20 – 8 = 12

f2 = 12

The mean of the following frequency distribu tion is 53. But the frequencies f1 and f2 in the classes 20-40 and 60-80 are missing. Find the missing frequencies: (2013)

 Classes Frequencies 0 – 20 15 20 – 40 F1 40 – 60 21 60 – 80 f2 80 – 100 17 Total 100

જવાબ :

2730 + 30f1 + 70f2 = 5300
30f1 + 70f2 = 5300 – 2730 = 2570
3f1 + 7f2 = 257 …[Dividing by 10
3f1 +7(47 – f1) = 257 . [From (A)
3f1 + 329 – 7f1 = 257
-4f1 = 257 – 329 = -72
f1 =  = 18
Putting the value of f1 in (A), we get
f2 = 47 – f1

f2 = 47 – 18 = 29
f1 = 18, f2 = 29

The lengths of leaves of a plant are measured correct to the nearest mm and the data obtained is represented as the following frequency distribution: (2015)

 Length No. of leaves 110 – 115 2 115 – 120 6 120 – 125 10 125 – 130 13 130 – 135 6 135 – 140 3 140 – 145 2

Draw a ‘more than type’ ogive for the above data.

જવાબ :

Following is the age distribution of dengue patients admitted in a hospital during a week of October, 2013: (2014)

 Weight No. of Students Less than 10 30 Less than 20 35 Less than 30 55 Less than 40 69 Less than 50 90 Less than 60 115 Less than 70 135 Less than 80 150

Draw a ‘less than type’ ogive for the above distribution. Also, obtain median from the curve.

જવાબ :

n/2 = 75

median =  43

The average score of boys in the examination of a school is 71 and that of the girls is 73. The average score of the school in the examination is 71.8. Find the ratio of number of boys to the number of girls who appeared in the examination. (2015)

જવાબ : Let the number of boys = n1
and number of girls = n2

No. of girls : No. of boys = 2 : 3

A medical camp was held in a school to impart health education and the importance of excercise to children. During this camp, a medical check of 35 students was done and their weights were recorded as follows: (2016)

 Weight No. of Students Below 40 3 Below 42 5 Below 44 9 Below 46 14 Below 48 28 Below 50 31 Below 52 35
Compute the modal weight.

જવાબ :

= 46.9kg

Heights of students of class X are given in the following frequency distribution: (2014)

 Height No. of Students 150 – 155 15 155 – 160 8 160 – 165 20 165 – 170 12 170 – 175 5

Find the modal height.

જવાબ :

Find the median for the following distribution: (2013)

 Class Frequency 0 – 10 6 10 – 20 10 20 – 30 12 30 – 40 8 40 – 50 8

જવાબ :

=25

Weekly income of 600 families is given below:

 Income No.of Families 0 – 1000 250 1000 – 2000 190 2000 – 3000 100 3000 – 4000 40 4000 – 5000 15 5000 – 6000 5

Find the median. (2012)

જવાબ :

= 1263.16

For helping poor girls of their class, students saved pocket money as shown in the following table: (2014)

 Class Frequency 5-7 6 7-9 3 9-11 9 11-13 5 13-15 7

Find mean and median for this data.

જવાબ :

= 10.33

Find the mean and median for the following data: (2015)

 Class Frequency 0 – 4 3 4 – 8 5 8 – 12 9 12 – 16 5 16 – 20 3

જવાબ :

=10

Find the mean of the following distribution by Assumed Mean Method: (2015)

 Class Interval Frequency 10 – 20 8 20 – 30 7 30 – 40 12 40 – 50 23 50 – 60 11 60 – 70 13 70 – 80 8 80 – 90 6 90 – 100 12

જવાબ :

Monthly pocket money of students of a class is given in the following frequency distribution:

 Pocket money No. of students 100 – 125 14 125 – 150 8 150 – 175 12 175 – 200 5 200 – 225 11

Find mean pocket money using step deviation method. (2014)

જવાબ :

The frequency distribution table of agricultural holdings in a village is given below: (2013)

 Area No. of families 1 – 3 25 4 – 6 22 7 – 9 52 10 – 12 45 13 – 15 16

Find the Mean area held by a family.

જવાબ :

=8.09

The mean of the following frequency distribution is 62.8. Find the missing frequency x. (2013)

 Class Frequency 0 – 20 5 20 – 40 8 40 – 60 X 60 – 80 12 80 – 100 17 100 – 120 8

જવાબ :

x=10

If the mean of the following distribution is 50, find the value of p: (2013)

 Class Frequency 0 – 20 17 20 – 40 P 40 – 60 32 60 – 80 24 80 – 100 19

જવાબ :

p=28

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4 , 10 , 7 , 7 , 6 , 9 , 3 , 8 , 9

 1 Mode A 7 2 Mean B 7 & 9 3 Sample standard deviation C 2.35

જવાબ :

1-B, 2-A, 3-C

62 , 65 , 68 , 70 , 72 , 74 , 76 , 78 , 80 , 82 , 96 , 101

 1 third quartile A 69 2 Median B 81 3 first quartile C 75

જવાબ :

1-B, 2-C, 3-A,

13, 18, 13, 14, 13, 16, 14, 21, 13

 1 Mean A 8 2 Median B 15 3 Mode C 14 4 Range D 13

જવાબ :

1-B, 2-C, 3-D, 4-A

1, 2, 4, 7

 1 Mean A 6 2 Median B None 3 Mode C 3 4 Range D 3.5

જવાબ :

1-D, 2-C, 3-B, 4-A

56,79,77,48,90,68,79,92,71

 1 Mean A 79 2 Median B 73.3 3 Mode C 77

જવાબ :

1-B, 2-C, 3-A

4,5,8,8,10,12,15,15,15,16

 1 Mean A 15 2 Median B 12 3 Mode C 11 4 Range D 10.8

જવાબ :

1-D, 2-C, 3-A, 4-B

63, 60, 57, 66, 62, 65, 69, 58

 1 Mean A 62.5 2 Median B None 3 Mode C 63.75

જવાબ :

1-C, 2-A, 3-B,

0.25, 0.34, 0.39, 0.38, 0.39, 1.67, 0.28, 0.30, 0.42, 0.46

 1 Mean A 0.39 2 Median B 0.385 3 Mode C 0.48

જવાબ :

1-B, 2-C, 3-A

154,163,164,168,170,179,185,188

 1 Mean A None 2 Median B 171.3 3 Mode C 169

જવાબ :

1-B, 2-C, 3-A

280, 280, 320, 350, 350, 350, 400, 410, 470, 490, 590

 1 Mean A 310 2 Mode B 390 3 Range C 350

જવાબ :

1-B, 2-C, 3-A