CBSE Solutions for Class 10 English

GSEB std 10 science solution for Gujarati check Subject Chapters Wise::

Real Numbers Polynomials Arithmetic Progressions Probability Coordinate Geometry Pair of Linear Equations in Two Variables Quadratic Equations Triangles Introduction to Trigonometry Some Applications of Trigonometry Circles Surface Areas and Volumes Statistics Areas related to Circles Constructions
The mean of 50 numbers is 18, the new mean will be …. if each observation is increased by 4  ( 22/24/20)

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જવાબ : 24


The sum of deviations of a set of values {a,b,c,d,e,f,g.h.i……} n items  measured from 26 is  -10 and the sum of deviations of the values from 20 is 50. The value of n is …(10/12/9) And mean of the items is ……. ( 19/18/17/25)

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જવાબ : 25


For a given data with 110 observations the ‘less than ogive’ and the ‘more then ogive’ intersect at (18, 20). The median of the data is …… (18/20/19)

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જવાબ : 18


The curve drawn by taking upper limits along x-axis and cumulative frequency along y-axis is ……….( less than ogive /more than ogive)

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જવાબ : less than ogive curve


The mean of five numbers is 40. If one number is excluded, their mean becomes 28. The excluded number is……. (68 / 88)

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જવાબ : 88


While computing mean of grouped data, we assume that the frequencies are centred at the ____________ of the classes

 

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જવાબ : class-marks


For drawing a frequency polygon of a continuous frequency distribution, we plot the Points whose ordinates are the frequencies of the respective classes and abscissae are respectively : 

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જવાબ : class marks of the classes


Find the mean of 32 numbers given mean of ten of them is 12 and the mean of other 20 is 9. And last 2 number is 10

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જવાબ : 10


The median and mean of the first 10 natural numbers.

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જવાબ : 5.5,5.5

 


Anand says that the median of 3, 14, 19, 20, 11 is 19. What doesn’t the Anand understand about finding the median?

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જવાબ : The dataset should be ascending order


The following observations are arranged in ascending order :
20, 23, 42, 53, x, x + 2, 70, 75, 82, 96
If the median is 63, find the value of x.

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જવાબ : 62


The mean of 20 observations was 60. It was detected on rechecking that the value of 125 was wrongly copied as 25 for computation of mean. Find the correct mean

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જવાબ : 65


Compute the Median for the given data

Class –interval

100-110

110-120

120-130

130-140

140-150

150-160

Frequency

6

35

48

72

100

4
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જવાબ : 136.11

 


In a continuous frequency distribution, the median of the data is 21. If each observation is increased by 5, then find the new median. (2015)

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જવાબ : New median = 21 + 5 = 26


From the following frequency distribution, find the median class: (2015)

Cost of living index     No. of weeks
1400- 1550     8
1550-1700     15
1700-1850     21
1850-2000    8
 

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જવાબ : Median class 1700 – 1850.


For one term, absentee record of students is given below. If mean is 15.5, then the missing frequencies x and y are:

Number of days

 0-5

 5-10

 10-15

 15-20

 20-25

 25-30

 30-35

 35-40

 TOTAL
Total Number of students

 15

 16

 x

 8

 y

 8

 6

 4

 70
 

 

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જવાબ : x = 7 and y = 6


The Median when it is given that mode and mean are 8 and 9 respectively, is:

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જવાબ : 8.67


If the arithmetic mean of x, x + 3, x + 6, x + 9 and x + 12 is 10, then x = ?

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જવાબ : 4


If the mean of first n natural numbers is 5n/9, then n =?

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જવાબ : 9


In a small scale industry, salaries of employees are given in the following distribution table:

Salary (in Rs.)

 4000 - 5000

 5000-6000

 6000-7000

 7000-8000

 8000-9000

 9000-10000
Number of employees

 20

 60

 100

 50

 80

 90
Then the mean salary of the employee is:

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જવાબ : Rs. 7450


In a hospital, weights of new born babies were recorded, for one month. Data is as shown:

Weight of new born baby (in kg)

 1.4 – 1.8

 1.8 – 2.2

 2.2 – 2.6

 2.6 – 3.0
No of babies

 3

 15

 6

 1
Then the median weight is:

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જવાબ : 2.05 kg


If 35 is removed from the data, 30, 34, 35, 36, 37, 38, 39, 40 then the median increases by ________

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જવાબ : 0.5


The Median when it is given that mode and mean are 8 and 9 respectively, is

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જવાબ : 8.67


The cumulative frequency table is useful in determining the ____________?

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જવાબ : Median


If the mean of 4 numbers, 2,6,7 and a is 15 and also the mean of other 5 numbers, 6, 18 , 1, a, b is 50. What is the value of b?

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જવાબ : The value of b = 180


The daily minimum steps climbed by a man during a week were as under:

Monday

Tuesday

Wednesday

Thursday

Friday

Saturday

35

30

27

32

23

28

Find the mean steps

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જવાબ : Mean = 29.17


A student scored the following marks in 6 subjects:

30, 19, 25, 30, 27, 30

Find his modal score.

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જવાબ : The mode is 30.


Find the mode of the following items.

0, 5, 5, 1, 6, 4, 3, 0, 2, 5, 5, 6

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જવાબ : the mode is = 5


While checking the value of 20 observations, it was noted that 125 was wrongly noted as 25 while calculating the mean and then the mean was 60. Find the correct mean.

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જવાબ : 65


Find the value of y from the following observations if these are already arranged in ascending order. The Median is 63.

20, 24, 42, y , y +2, 73, 75, 80, 99

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જવાબ : 61


Show that the mode of the series obtained by combining the two series S1 and S2 given below is different from that of S1 and S2 taken separately: (2015)
S1 : 3, 5, 8, 8, 9, 12, 13, 9, 9
S2 : 7, 4, 7, 8, 7, 8, 13

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જવાબ : In S1 : Number 9 occurs 3 times
∴ Mode of S1 Series = 9
In S2 : Number 7 occurs 3 times
∴ Mode of S, Series = 7
After combination:
In S1 & S2 : No. 8 occurs 4 times
∴ Mode of S1 & S2 taken combined = 8
So, mode of S1 & S2 combined is different from that of S1 & S2 taken separately.


Find the median of the data using an empirical formula, when it is given that mode = 35.3 and mean = 30.5. (2014)

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જવાબ : Mode = 3(Median) – 2(Mean)
35.3 = 3(X) – 2(30.5)
35.3 = 3(X) – 61
96.3 = 3 X
Median = 32.1


Find the mean of the 32 numbers, such that if the mean of 10 of them is 15 and the mean of 20 of them is 11. The last two numbers are 10.

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જવાબ : 390 /32


Find the mean of the first 11 natural numbers.

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જવાબ : 6


Find the mean of the following data. (2012)

Class

 Frequency
Less than 20

 15
Less than 40

 37
Less than 60

 74
Less than 80

 99
Less than 100

 120
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જવાબ :

= 52.5


The following table gives the literacy rate (in %) in 40 cities. Find the mean literacy rate: (2012)

Literacy rate

 No. of cities
45 – 55

4
55 – 65

 11
65 – 75

 12
75 – 85

 9
85 – 95

 4
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જવાબ :


The following table gives the daily income of 50 workers of a factory. Draw both types (“less than type” and “greater than type”) ogives. (2015)

Daily Income

 No. of workers
100-120

 12
120-140

 14
140-160

 8
160-180

 6
180-200

 10
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જવાબ :


In the table below, heart-beats of 30 women are recorded. If mean of the data is 76, find the missing frequencies x and y. (2014)

No. of heart beats

 No. of women
65-68

 x
68-71

 4
71-74

 3
74-77

 7
77-80

 8
80-83

 4
83-86

 y
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જવાબ :

⇒ 1978 + 66.5x + 84.5y = 2280
⇒ 1978 + 66.5x + 84.5(4 – x) = 2280 … [From (A)
⇒ 1978 + 66.5x + 338 – 84.5x = 2280
⇒ 1978 + 338 – 2280 = 84.5x – 66.5x
⇒ 36 = 18x ⇒ x = 2
From (A), y = 4 – x = 4 – 2 = 2 ∴ x = 2, y = 2


The mean of the following frequency distribution is 62.8 and the sum of frequencies is 50. Find the missing frequencies f1 and f2: (2013)

Classes
Frequencies
0 – 20
5
20 – 40
f1
40 – 60
20
60 – 80
f2
80 – 100
7
100 – 120
8
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જવાબ :

⇒ 2060 + 30f1 + 70f2 = 3140
⇒ 30f1 + 70f2 = 3140 – 2060 = 1080
⇒ 3f1 + 7f2 = 108 …[Dividing by 10
⇒ 3f1 + 7(20 – f1) = 108 … [From (A)
⇒ 3f1 + 140 – 7f1 = 108
⇒ -4f1 = 108 – 140 = -32 .
∴ f1 = 8
Putting the value of f1 into (A), we get
f2 = 20 – 8 = 12
∴ f2 = 12


The mean of the following frequency distribu tion is 53. But the frequencies f1 and f2 in the classes 20-40 and 60-80 are missing. Find the missing frequencies: (2013)

Classes

 Frequencies
0 – 20

 15
20 – 40

 F1
40 – 60

 21
60 – 80

 f2
80 – 100

 17
Total

 100
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જવાબ :

⇒ 2730 + 30f1 + 70f2 = 5300
⇒ 30f1 + 70f2 = 5300 – 2730 = 2570
⇒ 3f1 + 7f2 = 257 …[Dividing by 10
⇒ 3f1 +7(47 – f1) = 257 . [From (A)
⇒ 3f1 + 329 – 7f1 = 257
⇒ -4f1 = 257 – 329 = -72
⇒ f1 = \frac{-72}{-4} = 18
Putting the value of f1 in (A), we get
f2 = 47 – f1
⇒ f2 = 47 – 18 = 29
∴ f1 = 18, f2 = 29


The lengths of leaves of a plant are measured correct to the nearest mm and the data obtained is represented as the following frequency distribution: (2015)

Length

 No. of leaves
110 – 115

 2
115 – 120

 6
120 – 125

10
125 – 130

 13
130 – 135

 6
135 – 140

 3
140 – 145

 2

Draw a ‘more than type’ ogive for the above data.

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જવાબ :


Following is the age distribution of dengue patients admitted in a hospital during a week of October, 2013: (2014)

 

Weight

 No. of Students
Less than 10

 30
Less than 20

 35
Less than 30

 55
Less than 40

 69
Less than 50   

90
Less than 60

 115
Less than 70

 135
Less than 80

 150

Draw a ‘less than type’ ogive for the above distribution. Also, obtain median from the curve.

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જવાબ :

n/2 = 75

median =  43


The average score of boys in the examination of a school is 71 and that of the girls is 73. The average score of the school in the examination is 71.8. Find the ratio of number of boys to the number of girls who appeared in the examination. (2015)

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જવાબ : Let the number of boys = n1
and number of girls = n2

No. of girls : No. of boys = 2 : 3


A medical camp was held in a school to impart health education and the importance of excercise to children. During this camp, a medical check of 35 students was done and their weights were recorded as follows: (2016)
 

Weight

 No. of Students
Below 40

 3
Below 42

 5
Below 44

 9
Below 46

 14
Below 48

 28
Below 50

 31
Below 52

 35
Compute the modal weight.
 

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જવાબ :

= 46.9kg


Heights of students of class X are given in the following frequency distribution: (2014)
 

Height

 No. of Students
150 – 155

 15
155 – 160

 8
160 – 165

 20
165 – 170

 12
170 – 175

 5

Find the modal height.
 

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જવાબ :


Find the median for the following distribution: (2013)
 

Class

 Frequency
0 – 10

6
10 – 20

 10
20 – 30

 12
30 – 40

 8
40 – 50

 8
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જવાબ :

=25


Weekly income of 600 families is given below:

Income

No.of Families
0 – 1000

250
1000 – 2000

 190
2000 – 3000

 100
3000 – 4000

 40
4000 – 5000

 15
5000 – 6000

 5

Find the median. (2012)
 

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જવાબ :                      

= 1263.16


For helping poor girls of their class, students saved pocket money as shown in the following table: (2014)
 

Class

 Frequency
5-7

 6
7-9

 3
9-11

 9
11-13

 5
13-15

 7

Find mean and median for this data.
 

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જવાબ :

= 10.33


Find the mean and median for the following data: (2015)

Class

 Frequency
0 – 4

 3
4 – 8

 5
8 – 12

 9
12 – 16

 5
16 – 20

 3
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જવાબ :

=10


Find the mean of the following distribution by Assumed Mean Method: (2015)

Class Interval

 Frequency
10 – 20

8
20 – 30

 7
30 – 40

 12
40 – 50

 23
50 – 60

 11
60 – 70

 13
70 – 80

 8
80 – 90

 6
90 – 100

 12
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જવાબ :


Monthly pocket money of students of a class is given in the following frequency distribution:

Pocket money

No. of students
100 – 125

 14
125 – 150

8
150 – 175

 12
175 – 200

 5
200 – 225

 11

Find mean pocket money using step deviation method. (2014)
 

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જવાબ :


The frequency distribution table of agricultural holdings in a village is given below: (2013)

Area

 No. of families
1 – 3

 25
4 – 6

22
7 – 9

 52
10 – 12

 45
13 – 15

 16

Find the Mean area held by a family.
 

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જવાબ :

=8.09


The mean of the following frequency distribution is 62.8. Find the missing frequency x. (2013)

Class

 Frequency
0 – 20

5
20 – 40

 8
40 – 60

 X
60 – 80

 12
80 – 100

 17
100 – 120

 8
 

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જવાબ :

x=10


If the mean of the following distribution is 50, find the value of p: (2013)

Class

 Frequency
0 – 20

17
20 – 40

 P
40 – 60

 32
60 – 80

 24
80 – 100

 19
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જવાબ :

p=28


There are No Content Availble For this Chapter

4 , 10 , 7 , 7 , 6 , 9 , 3 , 8 , 9

1

Mode

A

7

2

Mean

B

7 & 9

3

Sample standard deviation

C

2.35
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જવાબ :

1-B, 2-A, 3-C

62 , 65 , 68 , 70 , 72 , 74 , 76 , 78 , 80 , 82 , 96 , 101

1

third quartile

A

69

2

Median

B

81

3

first quartile

C

75
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જવાબ :

1-B, 2-C, 3-A,

13, 18, 13, 14, 13, 16, 14, 21, 13

1

Mean

A

8

2

Median

B

15

3

Mode

C

14

4

Range

D

13
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જવાબ :

1-B, 2-C, 3-D, 4-A

1, 2, 4, 7

1

Mean

A

6

2

Median

B

None

3

Mode

C

3

4

Range

D

3.5
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જવાબ :

1-D, 2-C, 3-B, 4-A

56,79,77,48,90,68,79,92,71

1

Mean

A

79

2

Median

B

73.3

3

Mode

C

77
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જવાબ :

1-B, 2-C, 3-A

4,5,8,8,10,12,15,15,15,16

1

Mean

A

15

2

Median

B

12

3

Mode

C

11

4

Range

D

10.8
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જવાબ :

1-D, 2-C, 3-A, 4-B

63, 60, 57, 66, 62, 65, 69, 58

1

Mean

A

62.5

2

Median

B

None

3

Mode

C

63.75
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જવાબ :

1-C, 2-A, 3-B,

0.25, 0.34, 0.39, 0.38, 0.39, 1.67, 0.28, 0.30, 0.42, 0.46

1

Mean

A

0.39

2

Median

B

0.385

3

Mode

C

0.48
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જવાબ :

1-B, 2-C, 3-A

154,163,164,168,170,179,185,188

1

Mean

A

None

2

Median

B

171.3

3

Mode

C

169
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જવાબ :

1-B, 2-C, 3-A

280, 280, 320, 350, 350, 350, 400, 410, 470, 490, 590

1

Mean

A

310

2

Mode

B

390

3

Range

C

350
Hide | Show

જવાબ :

1-B, 2-C, 3-A

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Chapter 14 : Statistics

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